2 sin²x + 5 cosx - 4= 0⁰ < X < 360⁰
bantu
bantu
sin² x = 1 - cos²x
2 sin² x + 5 cos x + 1= 0
2 (1 - cos² x ) + 5 cos x + 1 =0
2 - 2 cos² x + 5 cos x + 1 =0
-2 cos² x + 5 cos x + 3= 0
(-2 cos x - 1)( cos x - 3 ) = 0
- 2 cos x - 1= 0 atau cos x - 3= 0
cos x = - 1/2 atau cos x = 3 (TM)
cos x = -1/2 = - cos 60 = cos (180- 60)
cos x = cos 120
x = 120 + k.360 atau x = -120 +k.360
k= 0, x =120 , x = -120
k = 1 , x = 480 (TM) atau x = 240
HP untuk 0 ≤ x ≤ 360 , x= { 120 , 240 }
tERBAIK YA...
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